%% Aufgabe 2 p_L = 1013; %hPa p_1 = 1013; p_2 = 1020; p_3 = 990; rho_Hg = 13.5; alpha_W = 20; %Grad gamma_W = 72.8; %mN/m alpha_Hg = 140; gamma_Hg = 470; d = 4; %mm g = 9.81; %% b) %% mmSaeule = @(dP,rho) dP*100/(g*rho)*1000; % rho in kg/m^3 p_mmW_2 = mmSaeule(p_2-p_L,rho_W*1000) p_mmW_3 = mmSaeule(p_3-p_L,rho_W*1000) p_mmHg_2 = mmSaeule(p_2-p_L,rho_Hg*1000) p_mmHg_3 = mmSaeule(p_3-p_L,rho_Hg*1000) %% d) %% hk = @(gamma,alpha,rho,r) (2*gamma*cosd(alpha))/(rho*g*r); hk_W = hk(gamma_W,alpha_W,rho_W*1000,d/2*0.001) hk_Hg = hk(gamma_Hg,alpha_Hg,rho_Hg*1000,d/2*0.001)