In the code editor, {$IF DECLARED()} is always highlighted as true, regardless of whether the symbol is actually present

• Lazarus version: 3.6

What happens

Text inside {$IF DECLARED(symbol)} blocks always appears active, even if the symbol specified is not actually declared anywhere. The {$ELSE} block is therefore shown as inactive. Replacing $IF with $IF NOT reverses the situation, but still does not make it depend on the observable reality.

I haven't tested, but other predicates such as OPTION() might have the same problem.

Steps to reproduce

program Project1;

begin

(* a variable from System unit *)

{$IF DECLARED(Output)}  // https://www.freepascal.org/docs-html/3.2.2/rtl/system/output.html
  WriteLn('declared Output');      // <-- shown as active, and actually is
{$ELSE}
  WriteLn('not declared Output');  // <-- shown as inactive, and actually is
{$ENDIF}

{$IF NOT DECLARED(StdErr)}  // https://www.freepascal.org/docs-html/3.2.2/rtl/system/stderr.html
  WriteLn('declared StdErr');      // <-- shown as inactive, actually active
{$ELSE}
  WriteLn('not declared StdErr');  // <-- shown as active, actually inactive
{$ENDIF}

(* non-existent symbol *)

{$IF DECLARED(symbol_that_DoEs_NoT_exist_asdfgsfds)}
  WriteLn('declared FOOBAR');      // <-- shown as active, actually inactive
{$ELSE}
  WriteLn('not declared FOOBAR');  // <-- shown as inactive, actually active
{$ENDIF}

{$IF NOT DECLARED(symbol_that_DoEs_NoT_exist_asdfgsfds)}
  WriteLn('declared FOOBAR');      // <-- shown as inactive, and actually is
{$ELSE}
  WriteLn('not declared FOOBAR');  // <-- shown as active, and actually is
{$ENDIF}

  ReadLn();
end.