Commit c46d729c authored by Jasin Goldkorn's avatar Jasin Goldkorn 🐨

added system ausfall information

parent 83958939
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......@@ -308,6 +308,12 @@
<td>Ausfall des Serveranbieters - "massive Probleme mit dem Cluster"</td>
<td>Ausfall des gesamten Systems</td>
</tr>
<tr>
<th scope="row">4</th>
<td>2019-06-129 15:44:30 - 2019-07-01 17:37:00</td>
<td>Unbekannt</td>
<td>Ausfall des gesamten Systems</td>
</tr>
</tbody>
</table>
</div>
......
<?php
87
6
Just wondering if there is something like .= for adding text to the beginning of a string, e.g.:
$foo =. 'bar';
which doesn't work.
Edit: example was originally $foo =. $bar; which can be achieved with $bar .= $foo;
php
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edited Jul 8 '14 at 16:19
asked Aug 18 '11 at 17:50
yuttadhammo
3,39955 gold badges2929 silver badges4242 bronze badges
4
$bar .= $foo? – James Allardice Aug 18 '11 at 17:52
I vouch for James' though he should have written an answer for it... – Christian Aug 18 '11 at 17:54
5
That appends $foo to $bar, instead of prepending $bar to $foo. The result is similar, but I think he wants to mutate $foo. Eric V Aug 18 '11 at 17:56
It was meant to be a bit of a tongue-in-cheek comment (which is why it's a comment, not an answer)! James Allardice Aug 18 '11 at 18:01
ugh... sorry, bad example... fixed now :) – yuttadhammo Aug 18 '11 at 18:21
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5 Answers
active oldest votes
133
Nope. But you can do
$foo = "bar" . $foo
shareedit
answered Aug 18 '11 at 17:52
Eric V
1,43111 gold badge1010 silver badges55 bronze badges
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4
You could always make your own function for that:
function prepend($string, $chunk) {
if(!empty($chunk) && isset($chunk)) {
return $string.$chunk;
}
else {
return $string;
}
}
$string would be the piece that you want to prepend and $chunk would be the text that you want something prepended onto it.
You could say the checks are optional, but by having that in there you don't need to worry about passing in a null value by accident.
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answered Aug 18 '11 at 18:03
Aaron
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1
Nicely done, but it doesn't really make things easier :) yuttadhammo Aug 18 '11 at 18:24
1
Thanks, you are right though. It's definitely not as easy or fast as something built in. Feel free to copy and paste if that helps make it easier :D Aaron Aug 18 '11 at 18:35
7
If something is !empty it's also always isset, no need for this double check. Furthermore, since $chunk is a required parameter of the function, it needs to be passed to the function or PHP will complain. This means this check can be abbreviated to if ($chunk) (to see if it's falsy a.k.a. "empty"). But, if $chunk doesn't contain anything, nothing will happen anyway. So this whole function body can be abbreviated to return $string . $chunk. Which means this whole function is pretty unnecessary. deceze Aug 19 '11 at 4:28
1
You can have a variable be set but also be empty. For example, a variable with the value of "" is empty but also set. – Aaron Aug 19 '11 at 16:02
1
Yes, but I'm saying your function is a very verbose way to write $foo . $bar. I challenge you to find any important case were your function does anything different. :) – deceze♦ Aug 20 '11 at 7:40
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3
I know this was asked/answered a while ago, but providing this answer as it is functionally equivalent despite it not being an assignment operator and no one commented on its usage for general string concatenation.
You may want to look into the use of the sprintf (documentation) family of functions for string concatenation. It provides a lot more sanitization and usability than just combining two strings with assignment operators.
$foo = 'foo';
$append = sprintf('%1$s%2$s', $foo, 'bar');
var_dump($append);
/* string(6) "foobar" */
$prepend = sprintf('%1$s%2$s', 'bar', $foo);
var_dump($prepend);
/* string(6) "barfoo" */
$prependInvert = sprintf('%2$s%1$s', $foo, 'bar');
var_dump($prependInvert);
/* string(6) "barfoo" */
$wrap = sprintf('%2$s%1$s%2$s', $foo, 'bar');
var_dump($wrap);
/* string(6) "barfoobar" */
I normally use vsprintf, since working with arrays is easier to manage value positions than individual arguments.
$vprepend = vsprintf('%2$s%1$s', array('foo', 'bar'));
var_dump($vprepend);
/* string(6) "barfoo" */
Also with an array of values, one can simply implode the resultant set of values for simple string concatenation.
var_dump(implode('', array('bar', 'foo')));
/* string(6) "barfoo" */
shareedit
edited Feb 25 '15 at 15:23
answered Feb 25 '15 at 15:07
fyrye
10.1k22 gold badges4040 silver badges5252 bronze badges
Unfortunately, I do not think sprintf() is as fast as simple concats. And it certainly doesn't seem nearly as syntax-friendly, either. See: stackoverflow.com/q/7147305/2430549 – HoldOffHunger Apr 9 '18 at 17:23
Correct, though not sure how you mean by syntax friendly. While it is not as fast or simplistic as concatenation. sprintf is commonly used throughout multiple languages. sprintf has its place and purpose on when to use it. eg. casting of multiple values or enforcing a number of inputs using sprintf, provides you with more functionality than simple concatenation when is required. See: 3v4l.org/8PWil But it should be not be used as a complete replacement for concatenation. – fyrye Apr 9 '18 at 22:46
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2
You can wrap the built-in function substr_replace, where the arguments $start and $length can be set to 0, which prepends the $replacement to $string and returns the result, like so:
function prepend(& $string, $prefix) {
$string = substr_replace($string, $prefix, 0, 0);
}
An example usage of the helper function would be:
$email_message = "Jonathan";
$appropriate_greeting = "Dear ";
prepend($email_message, $appropriate_greeting);
echo $email_message;
If you are into procedural programming, that is.
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answered Dec 6 '15 at 18:58
simon_
2811 silver badge77 bronze badges
I don't see the interest of using substr_replace; doing a simple $string = $prefix.$string; in the function will do the trick. Pierre-Olivier Vares Dec 27 '17 at 12:01
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1
Turning Blakethepatton's comment into an answer (thank you), a way to do this more neatly for longer variable names is by using a reference to the variable as follows:
$f = &$foo; $f = "bar{$f}";
This will save you typing over the answer by Eric V if your original variable name is 12 characters or longer.
An alternative on one line:
$f = 'bar' . ($f = &$foo);
shareedit
edited Apr 24 '18 at 13:47
answered Apr 24 '18 at 13:33
robrecord
1101010 bronze badges
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color: #33312E;
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{
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......@@ -123,3 +124,4 @@ html {
{
background-color: #12684e;
}
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